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- Arrhenius acids and bases
- Acid: Substance that, when dissolved in water, increases the
concentration of hydrogen ions (protons, H+).
- Base: Substance that, when dissolved in water, increases the
concentration of hydroxide ions.
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- Brønsted–Lowry: must have both
- 1. an Acid: Proton donor
- and
- 2. a Base: Proton acceptor
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- A Brønsted–Lowry acid…
- …must have a removable (acidic) proton.
- HCl, H2O, H2SO4
- A Brønsted–Lowry base…
- …must have a pair of nonbonding electrons.
- NH3, H2O
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- ...it is amphiprotic.
- HCO3–
- HSO4 –
- H2O
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- Water acts as a Brønsted–Lowry base and abstracts a proton (H+)
from the acid.
- As a result, the conjugate base of the acid and a hydronium ion are
formed.
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- From the Latin word conjugare, meaning “to join together.”
- Reactions between acids and bases always yield their conjugate bases and
acids.
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- Strong acids are completely dissociated in water.
- Their conjugate bases are quite weak.
- Weak acids only dissociate partially in water.
- Their conjugate bases are strong bases.
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- Substances with negligible acidity do not dissociate in water.
- Their conjugate bases are exceedingly strong.
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- HA(aq) + H2O(l) ⇄ H3O+(aq) + A-(aq)
- A B CA CB
- 2 substances that are connected by a donating and accepting of H2O
- really a “fight” over H+ between two bases: A- and H2O
- if A- has a greater affinity, lies to left
- if H2O has greater affinity, lies to right
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- In any acid-base reaction, the equilibrium favors the reaction that
moves the proton to the stronger base.
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- equilibrium expression where H+ is removed to form conjugate base
- so for: HA + H2O ⇄ H3O+ + A-
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- determined by equilibrium position of dissociation reaction
- strong acid:
- lies far to right, almost all HA is dissociated
- large Ka values
- creates weak conjugate base
- weak acid:
- lies far to left, almost all HA is stays as HA
- small Ka values
- creates strong conjugate base
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- diprotic: an acid with 2 acidic protons
- oxyacids: ex. HNO3
- most acids are this type
- where the acidic proton is attached to an oxygen
- organic acids: ex. CH3COOH
- containing a carboxyl group
- usually weak
- hydrohalic acids: ex. HBr
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- 2 water molecules exchange H+
- H2O + H2O ⇄ H3O+ +OH-
- Kw= [H3O+][OH-]= [H+][OH-]
- dissociation constant for water
- at 25C, [H+]=[OH-]=1.0 x 10-7
- so at 25C, Kw=1.0x10-14
- how will change it with temperature?
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- As we have seen, water is amphoteric.
- In pure water, a few molecules act as bases and a few act as acids.
- This process is called autoionization.
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- The equilibrium expression for this process is
- Kc = [H3O+] [OH–]
- This special equilibrium constant is referred to as the ion-product
constant for water, Kw.
- At 25°C, Kw = 1.0 ´
10-14
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- pH is defined as the negative base-10 logarithm of the hydronium ion
concentration.
- pH = –log [H3O+]
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- In pure water,
- Kw = [H3O+] [OH–] = 1.0 ´ 10-14
- Because in pure water [H3O+] = [OH-],
- [H3O+] = (1.0 ´ 10-14)1/2 = 1.0 ´ 10-7
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- Therefore, in pure water,
- pH = –log [H3O+]
- = –log (1.0 ´ 10-7) = 7.00
- An acid has a higher [H3O+] than pure water, so
its pH is <7
- A base has a lower [H3O+] than pure water, so its pH
is >7.
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- These are the pH values for several common substances.
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- The “p” in pH tells us to take the negative log of the quantity (in this
case, hydronium ions).
- Some similar examples are
- pOH –log [OH-]
- pKw –log Kw
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- Because
- [H3O+] [OH−] = Kw =
1.0 ´ 10-14,
- we know that
- –log [H3O+] + – log [OH−] = – log
Kw = 14.00
- or, in other words,
- pH + pOH = pKw = 14.00
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- Litmus paper
- “Red” paper turns blue above ~pH = 8
- “Blue” paper turns red below ~pH = 5
- An indicator
- Compound that changes color in solution.
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- pH meters
- measure the voltage in the solution
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- You will recall that the seven strong acids are HCl, HBr, HI, HNO3,
H2SO4, HClO3, and HClO4.
- These are strong electrolytes and exist totally as ions in aqueous
solution.
- For the monoprotic strong acids,
- [H3O+] = [acid].
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- Strong bases are the soluble hydroxides, which are the alkali metal (NaOH,
KOH)and heavier alkaline earth metal hydroxides (Ca(OH)2,
Sr(OH)2, and Ba(OH)2).
- Again, these substances dissociate completely in aqueous solution.
- [OH-] = [hydroxide added].
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- For a generalized acid dissociation,
- the equilibrium expression is
- This equilibrium constant is called the acid-dissociation constant, Ka.
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- The greater the value of Ka, the stronger the acid.
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- The pH of a 0.10 M solution of formic acid, HCOOH, at 25°C is 2.38. Calculate Ka for formic
acid at this temperature.
- We know that
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- The pH of a 0.10 M solution of formic acid, HCOOH, at 25°C is 2.38. Calculate Ka for formic
acid at this temperature.
- To calculate Ka, we need all equilibrium concentrations.
- We can find [H3O+], which is the same as [HCOO−],
from the pH.
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- pH = –log [H3O+]
- – 2.38 = log [H3O+]
- 10-2.38 = 10log [H3O+]
= [H3O+]
- 4.2 ´ 10-3
= [H3O+] = [HCOO–]
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- In the example:
- [A-]eq = [H3O+]eq
= 4.2 ´ 10-3
M
- [A-]eq + [HCOOH]eq = [HCOOH]initial
= 0.10 M
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- Percent Ionization =
´ 100
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- Calculate the pH of a 0.30 M solution of acetic acid, C2H3O2H,
at 25°C.
- Ka for acetic acid at 25°C is 1.8 ´ 10-5.
- Is acetic acid more or less ionized than formic acid (Ka=1.8
x 10-4)?
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- The equilibrium constant expression is:
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- pH = –log [H3O+]
- pH = – log (2.3 ´ 10−3)
- pH = 2.64
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- Have more than one acidic proton.
- If the difference between the Ka for the first dissociation
and subsequent Ka values is 103 or more, the pH
generally depends only on the first dissociation.
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- Bases react with water to produce hydroxide ion.
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- The equilibrium constant expression for this reaction is
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- Kb can be used to find [OH–] and, through it, pH.
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- What is the pH of a 0.15 M solution of NH3?
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- (1.8 ´ 10-5)
(0.15) = x2
- 2.7 ´ 10-6
= x2
- 1.6 ´ 10-3
= x2
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- Therefore,
- [OH–] = 1.6 ´ 10-3
M
- pOH = –log (1.6 ´ 10-3)
- pOH = 2.80
- pH = 14.00 – 2.80
- pH = 11.20
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- Ka and Kb are related in this way:
- Ka ´ Kb
= Kw
- Therefore, if you know one of them, you can calculate the other.
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- Anions are bases.
- As such, they can react with water in a hydrolysis reaction to form OH–
and the conjugate acid:
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- Cations with acidic protons (like NH4+) lower the
pH of a solution by releasing H+.
- Most metal cations (like Al3+) that are hydrated in solution
also lower the pH of the solution; they act by associating with H2O
and making it release H+.
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- Attraction between nonbonding electrons on oxygen and the metal causes a
shift of the electron density in water.
- This makes the O-H bond more polar and the water more acidic.
- Greater charge and smaller size make a cation more acidic.
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- An anion that is the conjugate base of a strong acid will not affect the
pH.
- An anion that is the conjugate base of a weak acid will increase the pH.
- A cation that is the conjugate acid of a weak base will decrease the pH.
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- Cations of the strong Arrhenius bases will not affect the pH.
- Other metal ions will cause a decrease in pH.
- When a solution contains both the conjugate base of a weak acid and the
conjugate acid of a weak base, the affect on pH depends on the Ka
and Kb values.
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- The more polar the H-X bond and/or the weaker the H-X bond, the more
acidic the compound.
- Acidity increases from left to right across a row and from top to bottom
down a group.
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- In oxyacids, in which an OH is bonded to another atom, Y,
- the more electronegative Y is, the more acidic the acid.
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- For a series of oxyacids, acidity increases with the number of oxygens.
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- Resonance in the conjugate bases of carboxylic acids stabilizes the
base and makes the conjugate acid more acidic.
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- Lewis acids are defined as electron-pair acceptors.
- Atoms with an empty valence orbital can be Lewis acids.
- A compound with no H’s can be a Lewis acid.
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- Lewis bases are defined as electron-pair donors.
- Anything that is a Brønsted–Lowry base is also a Lewis base. (B-L bases
also have a lone pair.)
- Lewis bases can interact with things other than protons.
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